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  • Basic Stress Equations

    2014 9 11 T D T D D D for solid circular shafts o for hollow shafts e o i j Rectangular Cross Section Torque z x y T Centroid τ Torsional Stress Cut Surface τ 1 2 a b Note a > b Cross Section Method 1 τmax = τ1 = T ⋅b3 ⋅a 1 8 ⋅bg ea2 ⋅b 2 j ONLY applies to the center of the longest side Method 2 τ α 1 2 1 2 2 = ⋅ ⋅ T a b a/b

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  • A Summary of Error Propagation

    2013 6 6 Example suppose you measure the height H of a door and get 2 00 0 03 m This means that H= 2 00 m and H= 0 03 m The door has a knob which is a height h= 0 88 0 04 m from the bottom of the door Then the distance from the doorknob to the top of the door is Q= H h= 1 12 m What is the uncertainty in Q Using equation 3 Q = p H 2 h 2 4

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  • Additional Exercises for Convex Optimization

    2021 1 5 gT h A b cT d 1 4 Dual of exponential cone The exponential cone K exp R3 is de ned as K exp = f xyz jy>0 yex=y zg Find the dual cone K exp We are not worried here about the ne details of what happens on the boundaries of these cones so you really needn t worry about it But we make some comments here for those who do care about such

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  • Lagrangian Mechanics

    2010 10 25 H q q t˙ = Xn σ=1 pσ q˙σ −L 6 26 Now we take the total time derivative of H dH dt = Xn σ=1 ˆ pσ q¨σ ˙pσ q˙σ − ∂L ∂qσ q˙σ − ∂L ∂q˙σ ¨qσ ˙ − ∂L ∂t 6 27 We evaluate H˙ along the motion of the system which entails that the terms in the curly brackets above cancel for each σ pσ = ∂L ∂q

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  • 4 3 Applications of Energy Balance

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  • EE364a Homework 2 solutions

    2021 3 29 EE364a Winter 2007 08 Prof S Boyd EE364a Homework 2 solutions 2 28 Positive semidefinite cone for n = 1 2 3 Give an explicit description of the positive

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  • Conic Sections Parabola Ellipse Hyperbola Circle

    For the parabola the standard form has the focus on the x axis at the point a 0 and the directrix is the line with equation x = −a In standard form the parabola will always pass through the origin Circle x 2 y2=a2 Ellipse x 2 /a 2 y 2 /b 2 = 1 Hyperbola x 2 /a 2 y 2 /b 2 = 1

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  • 13 CALCULUS OF VECTOR VALUED FUNCTIONS

    2014 1 29 Let C be the curve r t = t cost tsin t t a Show that C lies on the cone x2 y2 = z2 b Sketch the cone and make a rough sketch of C on the cone solution x = t cost y = t sin t and z = t hence x2 y2 = t2 cos2 t t2 sin2 t = t2 cos2 t sin2 t = t2 = z2 x2 y2 = z2 is the equation of a circular cone hence the curve lies on a circular

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  • Basic Stress Equations

    2014 9 11 T D T D D D for solid circular shafts o for hollow shafts e o i j Rectangular Cross Section Torque z x y T Centroid τ Torsional Stress Cut Surface τ 1 2 a b Note a > b Cross Section Method 1 τmax = τ1 = T ⋅b3 ⋅a 1 8 ⋅bg ea2 ⋅b 2 j ONLY applies to the center of the longest side Method 2 τ α 1 2 1 2 2 = ⋅ ⋅ T a b a/b

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    2020 1 22 6 LE 2018 058043N18 3 a NOT TO SCALE 8 cm 17 cm The diagram shows a solid cone The radius is 8 cm and the slant height is 17 cm i Calculate the curved surface area of the cone The curved surface area A of a cone with radius r and slant height l is Ar= r l cm 2 2 ii Calculate the volume of the cone The volume V of a cone with radius r and height h is Vr h

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  • STEADY HEAT CONDUCTION

    2014 1 13 where R conv K/W 3–8 is the thermal resistanceof the surface against heat convection or simply the convection resistanceof the surface Fig 3–4 Note that when the convec tion heat transfer coefficient is very large h → the convection resistancebecomes zero and T s T That is the surface offers no resistance to convec tion and thus it does not slow down the heat transfer process

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  • The Hamiltonian method

    2019 10 16 We then showed in Claim 6 3 that dE=dt = ¡ L= t This implies that if L= t = 0 that is if t doesn t explicitly appear in L then E is constant in time In the present chapter we will examine many other properties of this quantity E or more precisely the quantity H the Hamiltonian that arises when E is rewritten in a certain way

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  • The Hamiltonian method

    2019 10 16 We then showed in Claim 6 3 that dE=dt = ¡ L= t This implies that if L= t = 0 that is if t doesn t explicitly appear in L then E is constant in time In the present chapter we will examine many other properties of this quantity E or more precisely the quantity H the Hamiltonian that arises when E is rewritten in a certain way

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  • Volume of Cone

    Q 2 If the height of a given cone is 7 cm and the diameter of the circular base is 6 cm Then find its volume Solution Diameter of the circular base = 6 cm So radius = 6/2 = 3 cm Height = 7 cm By the formula of cone volume we know V = 1/3 πr 2 h So by putting the values of r and h we get

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  • EE364a Homework 2 solutions

    2021 3 29 EE364a Winter 2007 08 Prof S Boyd EE364a Homework 2 solutions 2 28 Positive semidefinite cone for n = 1 2 3 Give an explicit description of the positive

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    2016 3 11 De ne N1 X = freal vector space of all 1 cyclesg=f1 cycles with intersection 0 with all hypersurfacesg The fundamental fact is that the real vector space N1 X is nite dimensional In this vector space we de ne the e ective convex cone NE X as the set of all linear combinations with nonnegative coe cients of classes of curves in X

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  • Staedy Conduction Heat Transfer

    2015 9 30 Q hA T T W Conv s Rconv is the thermal resistance of the surface against heat convection or simply the convection resistance of the surface Thermal radiation between a surface of area A at Ts and the surroundings at T∞ can be expressed as m K W h T T T T h A R W R T T Q A T T h A T T rad s s rad rad rad s rad s rad s 2 2 2 4 4 1

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  • STEADY HEAT CONDUCTION

    2014 1 13 where R conv K/W 3–8 is the thermal resistanceof the surface against heat convection or simply the convection resistanceof the surface Fig 3–4 Note that when the convec tion heat transfer coefficient is very large h → the convection resistancebecomes zero and T s T That is the surface offers no resistance to convec tion and thus it does not slow down the heat transfer process

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  • A Summary of Error Propagation

    2013 6 6 Example suppose you measure the height H of a door and get 2 00 0 03 m This means that H= 2 00 m and H= 0 03 m The door has a knob which is a height h= 0 88 0 04 m from the bottom of the door Then the distance from the doorknob to the top of the door is Q= H h= 1 12 m What is the uncertainty in Q Using equation 3 Q = p H 2 h 2 4

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  • Conic Sections Parabola Ellipse Hyperbola Circle

    For the parabola the standard form has the focus on the x axis at the point a 0 and the directrix is the line with equation x = −a In standard form the parabola will always pass through the origin Circle x 2 y2=a2 Ellipse x 2 /a 2 y 2 /b 2 = 1 Hyperbola x 2 /a 2 y 2 /b 2 = 1

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  • HEAT CONDUCTION EQUATION H

    2014 1 15 65 CHAPTER 2 The notation T x on the other hand indicates that the temperature varies in the x direction only and there is no variation with the other two space coordi nates or time Steady versus Transient Heat Transfer Heat transfer problems are often classified as being steady also called steady state or transient also called unsteady The term steady implies no change

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  • HEAT CONDUCTION EQUATION H

    2014 1 15 65 CHAPTER 2 The notation T x on the other hand indicates that the temperature varies in the x direction only and there is no variation with the other two space coordi nates or time Steady versus Transient Heat Transfer Heat transfer problems are often classified as being steady also called steady state or transient also called unsteady The term steady implies no change

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  • 13 CALCULUS OF VECTOR VALUED FUNCTIONS

    2014 1 29 Let C be the curve r t = t cost tsin t t a Show that C lies on the cone x2 y2 = z2 b Sketch the cone and make a rough sketch of C on the cone solution x = t cost y = t sin t and z = t hence x2 y2 = t2 cos2 t t2 sin2 t = t2 cos2 t sin2 t = t2 = z2 x2 y2 = z2 is the equation of a circular cone hence the curve lies on a circular

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  • Volume of Cone

    Q 2 If the height of a given cone is 7 cm and the diameter of the circular base is 6 cm Then find its volume Solution Diameter of the circular base = 6 cm So radius = 6/2 = 3 cm Height = 7 cm By the formula of cone volume we know V = 1/3 πr 2 h So by putting the values of r and h we get

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  • Why is my keyboard typing wrong characters

    2021 8 9 I have a logik keyboard for pc and this what my keyboard gives instead q gives ` w opens help box on whatever programme is open r gives 5 u gives 6 I gives = p givesg gives b h gives n

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